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D Is the midpoint of hypotenuse …

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D Is the midpoint of hypotenuse AC of a right angle triangle ABC. prove that BD=1/2 AC.
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My Guide ... 4 years ago

Let ∆ABC is a right triangle such that ∠B = 90 and D is mid point of AC . then we have to prove that BD = 1/2 AC we produce BD to E such that BD = AC and EC.   Now is ∆ADB and ∆CDE we have  AD = DC [Given]  BD = DE [By construction]  And, ∠ADB = ∠CDE [Vertically opposite angles]  ∴ By SAS criterion of congruence we have  ∆ADB ≅ ∆CDE  ⇒ EC = AB and ∠CED = ∠ABD ....(i) [By cpctc]  But ∠CED & ∠ABD are alternate interior angles  ∴ CE ║ AB ⇒ ∠ABC + ∠ECB = 1800 [Consecutive interior angles] ⇒ 90 + ∠ECB = 1800  ⇒ ∠ECB = 900  Now, In ∆ABC & ∆ECB we have  AB = EC [By (i)]  BC = BC [Common]  And, ∠ABC = ∠ECB = 900  ∴ BY SAS criterion of congruence  ∆ABC ≅ ∆ECB  ⇒ AC = EB [By cpctc]  ⇒ 1/2 AC = 1/2 EB  ⇒ BD = 1/2 AC
http://mycbseguide.com/examin8/

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