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Find the sum of the first 15 multiples of 8( arithmetic progression)

Posted by Venkataramana Shenoy 5 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Karan Chauhan 5 years, 1 month ago

The answer is 960

0Thank You

Yogita Ingle 5 years, 1 month ago

The first 8 multiples of 8 are
8, 16, 24, 32, 40, 48, 56,64
These are in an A.P., having first term as 8 and common difference as 8.
Therefore, a = 8
d = 8
S15 = ?
S_n = n/2 [2a + (n - 1)d]
S₁₅ = 15/2 [2(8) + (15 - 1)8]
= 15/2[6 + (14) (8)]
= 15/2[16 + 112]
= 15(128)/2
= 15 × 64
= 960

1Thank You

Venkataramana Shenoy 5 years, 1 month ago

The answer is 960

0Thank You

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