No products in the cart.

  1. Homework Help
  2. CBSE
  3. Class 09
  4. Mathematics

Find the value of k so …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Install Now
Find the value of k so that (1,-3) is the solution of the equation x-2y=k

    • Posted by Samiksha Singaraj 💫 4 years ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Samiksha Singaraj 💫 3 years, 11 months ago

    Thanks buddy

    0Thank You

    Gaurav Seth 4 years ago

    (1,-3) = (x,y)

    x= 1

    y=-3

    now we will put these values in equation;x - 2y =k

    1 - 2 X (-3) = k    

    1 + 6 = k ( because - and - will change in + )

    and

    then

    k= 7.

     

     

    1Thank You

    ANSWER
    http://mycbseguide.com/examin8/

    Related Questions

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

    Few rules to keep homework help section safe, clean and informative.
    • Don't post personal information, mobile numbers and other details.
    • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
    • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
    • Ask specific question which are clear and concise.

    Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

    Posted by T Prudhvi 2 days, 3 hours ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    The polynomial of the type ax²+bx+c,a=0 is called

    • Posted by Gnani Yogi 2 months, 3 weeks ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    X³-12x²+39x-28

    • Posted by Sukhi Devasi 2 months, 3 weeks ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    sides of a triangle are in the ratio of 12:17:25 and its perimeter is 540cm. find its area

    • Posted by Akhilesh Patidar 2 months, 3 weeks ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    Cost of a pen is two and half times the cost of a pencil. Express the situation as a linear equation in two variables

    • Posted by Kirshika Ganesh 2 months, 3 weeks ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    2x+5y

    • Posted by Yash Pandey 2 months, 3 weeks ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    Ch-1 introduction

    • Posted by Sheikh Alfaz 5 days, 19 hours ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    What is 38747484±393884747

    • Posted by Alvin Thomas 2 months, 3 weeks ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    3√2×4√2×12√32

    • Posted by Manas Khurana 2 months, 3 weeks ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    Prove that the sum of all the three interior angles of a triangle is 180 degree

    • Posted by Savitha Savitha 2 months, 3 weeks ago

    CBSE > Class 09 > Mathematics
    • 0 answers

    myCBSEguide App

    myCBSEguide

    Trusted by 1 Crore+ Students

    Install Now

    Test Generator

    Test Generator

    Create papers online. It's FREE.

    Try Now

    CUET Mock Tests

    CUET Mock Tests

    75,000+ questions to practice only on myCBSEguide app

    Install Now
    Google Play

    Download myCBSEguide App

    All Courses

    Other Websites

    CBSE Courses

    Resources

    Corporate

    NCERT Solutions

    CBSE Sample Papers

    All Content and Intellectual Property is under Copyright Protection | myCBSEguide.com ©2007-2024