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Challenge!!! Solve for x: $$\dfrac{d}{d cosx} …

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Challenge!!!
Solve for x:
$$\dfrac{d}{d cosx} (sinx)$$

    • Posted by ⠀ 4 years, 5 months ago

    CBSE > Class 11 > Mathematics
    • 4 answers

    Ayush Kashyap 4 years, 5 months ago

    Answer is cot x

    1Thank You

    ? S. S. ? 4 years, 5 months ago

    Let u =sinx and v= cosx .....d(sinx)/d (cosx)......d(u/v)= (v du + u dv )/ v²..... [ cosx × d(sin x) - sinx × d(cosx)] / (cosx)² Since, d(sin x) = cos x and d(cos x) = -sin x Therefore, [(cosx)² + (Sinx)²]/ (cosx)²= 1/ (cos x)²=(secx)²

    1Thank You

    ? S. S. ? 4 years, 5 months ago

    Mera toh kuch or hii answer arha hai...?sec²x....

    0Thank You

    ⠀ 4 years, 5 months ago

    Not x but solve it

    0Thank You

    ANSWER
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