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Sum of the area of two …

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Sum of the area of two squares is 468 meters square .If the difference of their perimeter is 24 m, find the sides of the squares?
  • 4 answers

Chandu G 5 years, 1 month ago

Ur welcome ☺☺

Taniya 5 years, 1 month ago

Thank you so much ??.

Chandu G 5 years, 1 month ago

. Let perimeter of first square = x metres Let perimeter of second square = (x + 24) metres Length of side of first square = metres {Perimeter of square = } Length of side of second square = metres Area of first square = side × side =  Area of second square =  According to given condition:  ⇒  ⇒  ⇒ =  ⇒ = 7488 ⇒ = 0 ⇒ = 0 Comparing equation =0 with standard form , We get a = 1, b =24 and c = −3456 Applying Quadratic Formula   ⇒  ⇒  ⇒  ⇒ x = 48, −72 Perimeter of square cannot be in negative. Therefore, we discard x=−72. Therefore, perimeter of first square = 48 metres And, Perimeter of second square = x + 24 = 48 + 24 = 72 metres ⇒ Side of First square =  And, Side of second Square = 

Chandu G 5 years, 1 month ago

Side of 1st square is 18m and side of 2nd square is 12m
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