A toy gun with a spring …
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A toy gun with a spring which is compressed 3cm is used to project a stone of mass 50 gm to height of 10cm. Calculate the potential energy of the spring. How much it should be compressed to throw the stone to 5m. Find out the spring constant associated with the spring
Posted by Annapoorna Madhu 4 years, 1 month ago
- 1 answers
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Gaurav Seth 4 years, 1 month ago
To reach the peak of 10m the energy of spring must be
Mass = 50g = 50/1000kg = 0.05kg
acceleration due to gravity = g m/s^2 (take it as 10m/s^2 or 9.8 m/s^2 as directed in question)
Height = 10m
P = mgh
= 0.05 X g X 10 J
= 0.5g J
a) The potential energy of spring to throw it to height 10m is = 0.5g J
Taking g = 10; its 5j
b) To throw obhect to any height 'H' :
Let force coefficent of spring be = k
k X 0.03 = 5
k = 500/3
To throw it to any height H; compression c should be :
k( c) = mgH
500/3 X c = 0.05 X 10 X H
c = 0.05 X 10 X H X 3/500
Substitute the value of any H, to find out c (how much it needs to be compresssed. c is in metres.
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