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Find the values of k for …

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Find the values of k for which following equation has real roots kx ( x-3) + 9 = 0

    • Posted by Manthan Singhal 5 years, 1 month ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Manthan Singhal 5 years, 1 month ago

    This is for real and equal I want to know for real roots so it can be distinct also

    0Thank You

    Yogita Ingle 5 years, 1 month ago

    Given, Quadratic Equation is kx(x - 3) + 9 = 0.

    ⇒ kx² - 3kx + 9 = 0

    On comparing with ax² + bx + c = 0, we get a = k, b = -3k, c = 9.

    Given that the equation has real equal and real roots.

    ∴ D = 0

    b² - 4ac = 0

    ⇒ (-3k)² - 4(k)(9) = 0

    ⇒ 9k² - 36k = 0

    ⇒ 9k² = 36k

    ⇒ 9k = 36

    ⇒ k = 36/9

    ⇒ k = 4

    2Thank You

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