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Is anyone can explain me q no 2 of ex. 6.4

    • Posted by Sufiya Naaz 5 years, 1 month ago

    CBSE > Class 07 > Mathematics
    • 2 answers

    Amarabati Parida 5 years, 1 month ago

    Q no.2 -If we take any point O in the interior of a triangle PQR and join OR, OP, OQ. Then, we get three triangles ΔOPQ, ΔOQR and ΔORP is shown in the figure below. We know that, The sum of the length of any two sides is always greater than the third side. (i) Yes, ΔOPQ has sides OP, OQ and PQ. So, OP + OQ > PQ (ii) Yes, ΔOQR has sides OR, OQ and QR. So, OQ + OR > QR (iii) Yes, ΔORP has sides OR, OP and PR. So, OR + OP > RP

    0Thank You

    Amarabati Parida 5 years, 1 month ago

    The sum of the length of any two sides is always greater than the third side. Now consider the ΔABC, Here, AB + BC > CA … [equation i] Then, consider the ΔBCD Here, BC + CD > DB … [equation ii] Consider the ΔCDA Here, CD + DA > AC … [equation iii] Consider the ΔDAB Here, DA + AB > DB … [equation iv] By adding equation [i], [ii], [iii] and [iv] we get, AB + BC + BC + CD + CD + DA + DA + AB > CA + DB + AC + DB 2AB + 2BC + 2CD + 2DA > 2CA + 2DB Take out 2 on both the side, 2(AB + BC + CA + DA) > 2(CA + DB) AB + BC + CA + DA > CA + DB I think the process was too lengthy, but I hope you understand ?

    2Thank You

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