A cubical box has each edge …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Shree Vanshika Reddy Reddy 1 month, 4 weeks ago
- 0 answers
Posted by Bhargav Panchal Shantilal Panchal 1 year, 3 months ago
- 2 answers
Posted by Vedika Chourasiya 1 year ago
- 0 answers
Posted by Dipratna Salunke 1 year, 3 months ago
- 2 answers
Posted by Harsha Sarji.S 1 year, 1 month ago
- 0 answers
Posted by Shivanshu Pandey 1 year, 3 months ago
- 0 answers
Posted by Shree Vanshika Reddy Reddy 7 months, 1 week ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Gaurav Seth 5 years, 1 month ago
(i) Lateral surface area of cubical box = 4a2 = 4 x 102 = 400 cm2
Lateral surface area of cuboidal box = 2h (l + b)
= 2 x 8(12.5 +10) = 16 X 22.5 = 360 cm2
Thus, lateral surface area of cubical box is greater by
(400 cm2 - 360 cm2) = 40 cm2
(ii) Total surface area of cubical box = 6a2 = 6 x 102 cm2 = 600 cm2
Total surface area of cuboidal box = 2 (lb + bh + hl)
= 2(12.5 x 10 + 10 x 8 + 8 x 12.5)
= 2(125 + 80 + 100) = 2 x 305cm2 = 610 cm2
Thus, total surface area of cuboidal box is greater by (610 - 600) cm2
= 10 cm2
1Thank You