Sec theta ( 1-sin theta) ( …

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Gaurav Seth 5 years, 1 month ago
= secA (1-sinA) (secA+tanA)
= secA (secA + tanA - sinA secA - sinA tanA)
= 1/cosA [1/cosA + sinA/cosA - sinA/cosA - sin²A/cosA]
= 1/cosA [1/cosA - sin²A/cosA]
= 1/cosA [(1-sin²A)/cosA]
= 1/cosA [cos²A/cosA]
=1
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