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A triangle having sides a, b …

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A triangle having sides a, b and c. If s-a=4cm, s-b=8 cm and s-c=12 cm, then find the value of a, b and c.

    • Posted by Ashmit Sharma 4 years ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Gaurav Seth 4 years ago

    Answer:

    Sides of the triangle are 20 cm, 16 cm, 12 cm

    Step-by-step explanation:

     

    Formula used:

     

    If a, b, c are sides of triangle then

     

    s=(a+b+c)/2

     

     

    Given:

    s-a=4 cm

     

    s-b=8 cm

     

    s-c=12 cm

     

     

    Adding these we get

     

    s+s+s-a-b-c = 24

     

    3s-(a+b+c) =24

     

    3s-2s = 24

     

    s = 24

     

     

    Now,

     

    s-a=4

     

    24 - a =4

     

    a = 24 - 4 = 20 cm

     

    s-b=8

     

    24 - b = 8

     

    b = 24 - 8 = 16 cm

     

    s - c = 12

     

    24 - c = 12

     

    c = 24 -12 = 12 cm

    2Thank You

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