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man observes from the top of a 50m high lighthouse from the sea level, the angles of depression of two ships are 45°and 60° . if one ship is exactly behind the other on the same side of the light house, then find the distance between the two ships.

Posted by S Sibiraj 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Prakhar Pare 5 years, 1 month ago

Sorry but not been able to attach photo In ∆ABC tan60°= AB\BC √3 = 50\ BC BC= 50/√3 BC=50\√3 *√3/√3 ( by rationalisation) BC=50√3/3 meter In∆ABD tan 45° = AB/DB 1= AB/DB y= 50/1 y=50 meter BC+x = y 50√3/3+x = 50 x=50-50√3/3 x=150-50√3/3 ( by taking LCM) x=50(3-√3)/3 ( by taking common) ANS: 50(3-√3)/3 meter

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X-y=5

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CBSE > Class 10 > Mathematics

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Posted by Hari Anand 5 months, 1 week ago

CBSE > Class 10 > Mathematics