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in triangle ABC right angled at B,angle A =angleC find value of sinA cosC+cosA sinC

Posted by S Sibiraj 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 1 month ago

Answer:

The value=1

Step-by-step explanation:

∠B=90°

∠A=∠C

Hyp= AC

Other sides= BC, AB

sinA= BC/AC

cosA=AB/AC

sinC= AB/AC

cosC= BC/AC

Using Pythagoras Theorem

AC²=BC²+AB²

sinA cosC+cosA sinC

=BC/AC*BC/AC +AB/AC*BC/AC

=BC²/AC² +AB²/AC²

=AB²+BC/AC²

=AC²/AC²

4Thank You

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