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If tan 2A=cot(A-18°), where 2A is …

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If tan 2A=cot(A-18°), where 2A is an acute angle, find the value of A.

Posted by Aditya Chauhan 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 1 month ago

Given tan2A=cot(A−180)

⇒cot(90−2A)=cot(A−180)[∵tanθ=cot(90−θ)]

Comparing angles we get

90−2A=A−18

⇒90+18=A+2A

⇒3A=108

⇒A=108/3

⇒A=36∘

2Thank You

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CBSE > Class 10 > Mathematics