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In a circle of radius 5cm, …

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In a circle of radius 5cm, AB and AC are the two chords such that AB=AC=6cm . Find the length of the chord BC. answer is 9.6cm if this is your answer then Please explain it.

Posted by Vandana 🇮🇳 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Vandana 🇮🇳 5 years, 1 month ago

Thank you soo much?? Are u student or teacher?

1Thank You

Gaurav Seth 5 years, 1 month ago

Given - AB and AC are two equal words of a circle, therefore the centre of the circle lies on the bisector of BAC.

OA is the bisector of BAC.

Again, the internal bisector of an angle divides the opposite sides in the ratio of the sides containing the angle.

P divides BC in the ratio = 6 : 6 = 1 : 1.

P is mid-point of BC.

OP BC.

In ABP, by Pythagoras theorem,

In right OBP, we have

Equating (1) and (2), we get

Putting AP in (1), we get

or,alternate method:

Area of AOB by Heron's formula

arAOB) =

Also arAOB =

BM = h = 4.8 cm

BC = 2 BM = 9.6 cm.

2Thank You

ANSWER

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