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Water flows through a circular pipe, …

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Water flows through a circular pipe, whose internal diameter is 2 cm, at the rate of 0.7 m per second into a cylindrical tank, the radius of whose base is 40 cm. By how much will the level of water in the cylindrical tank use in half an hour?

Posted by Manish Agarwal 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Manish Agarwal 5 years, 1 month ago

Thank you Gaurav ☺️

Gaurav Seth 5 years, 1 month ago

Given diameter of the circular pipe = 2 cm

So, the radius of the circular pipe = 2/2 = 1 cm

Height of the circular pipe = 0.7 m = 0.7 * 100 = 70 cm

Now, volume of the water flows in 1 second = πr² h

= 3.142 * 1² * 70

= 3.142 * 70

Volume of the water flows in 1/2 hours = 3.142 * 70 * 30 * 60

Now, volume of the water flows = Volume of the cylinder

=> 3.142 * 70 * 30 * 60 = πr² h

=> 3.142 * 70 * 30 * 60 = 3.142 * (40)² h

=> 70 * 30 * 60 = 40 * 40 * h

=> h = (70 * 30 * 60)/(40 * 40)

=> h = (70 * 3 * 6)/(4 * 4)

=> h = 1260/16

=> h = 78.85 cm

So, the level of water rise in the tank in half an hour is 78.75 cm

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