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A wire had a 20 resistance …

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A wire had a 20 resistance . It was then melted and Reduced to one-fifth of its original length and its cross section area was doubled.find its new Resistance.

Posted by ?Isha .B 5 years, 2 months ago

CBSE > Class 10 > Science

1 answers

Yogita Ingle 5 years, 2 months ago

R = ρ* L/A

R ∝ L And R ∝ 1/A

here, length is reduced to 1/5 times so resistance also reduced to 1/5 times

so, resistance is 20/5 Ω = 4 Ω

Again, Area is doubled so resistance get half.

so, New resistance is 4/2Ω = 2Ω

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CBSE > Class 10 > Science