What will be the stopping distance …
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Posted by Kajal Vishwakarma 5 years ago
- 1 answers
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Yogita Ingle 5 years ago
If the initial velocity is doubled, Then the stopping distance become 4 times.
From the third equation,
{tex}v^2=u^2-2as{/tex}
{tex}u^2= v^2+2as{/tex}
From this equation distance (s) is directly proportional to u^2.
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