The sum of first 5 multiple …

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Yogita Ingle 5 years, 1 month ago
Sum of first 5 multiples of 3:
Sum of an AP is: n/2 × (2a+(n−1)d)
a=3,d=3,n=5
Then,
Sum = 5/2 ×(2×3+(5−1)×(3))
= 5/2 ×(6+12)
= 5/2 ×18
= 5 ×9
= 45
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