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find k for real roots 2x²+kx+3=0

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find k for real roots 2x²+kx+3=0

Posted by Aayush Gupta 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

........ ...... 5 years, 1 month ago

Here, a=2, b=k, c=3 D=b^2-4ac/2a =k^2-4×2×3/2×2 =K^2-24/4=0 k^2=24 K=√24 .......It may helpful to you.

0Thank You

Yogita Ingle 5 years, 1 month ago

We have to find the values of k for quadratic equations 2x² + kx + 3 = 0 so that they have two equal roots.

we know, quadratic equation will be equal only when

discriminant, D = b² - 4ac = 0

on comparing 2x² + kx + 3 = 0 with general form of quadratic equation , ax² + bx + c = 0 we get, a = 2, b = k and c = 3

so Discriminant , D = (k)² - 4(2)(3) = 0

or, k² - 24 = 0

or, k = ± √24 = ±2√6

hence, the value of k = 2√6 or -2√6

3Thank You

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