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How many three digit number are divisible by 7

Posted by Shashank Singh 8 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Hans Raj 8 years, 1 month ago

the first 3 digit number = 105

last 3 digit no = 994

105,112,119...... 994 forms an AP

a=105

d=7

an=994

n=?

an=a+(n-1)d

994=105+(n-1)7

889=7n - 7

896=7n

n=128

hence there are 128 three digit numbers which are divisible by7

0Thank You

Janhavi Sharma 8 years, 1 month ago

The first three digit number which is divisible by 7 is 105 and last three digit number which is divisible by 7 is 994. This is an A.P. in which a = 105, d = 7 and l = 994. Let the number of terms be n . Then tn = 994. nth term of A.P = tn = a + (n - 1)d. ⇒ 994 = 105 + (n -1)7. ⇒ 889 = 7(n-1) ⇒ n -1 = 127 ∴ n = 128. ∴ There are128 three digit numbers which are divisible by 7

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CBSE > Class 10 > Mathematics