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Given sin(A+B)=SinA cosB +cosA sinB then …

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Given sin(A+B)=SinA cosB +cosA sinB then find the value of sin 75°

Posted by Nikhil Joshi 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Manpreet Yadav 5 years, 1 month ago

Let A=45°,B=30° (so that sum of A and B =75° and we can get Sin74°) (put the value of A and B in equation) - Sin75°=Sin45°*Cos30° + Cos 45°*Sin30° - Sin75° = 1/√2*√3/2 + 1/√2*1/2 - Sin75° = √3/2√2 + 1/2√2 - Sin75° = (√3+1)/2√2 Sin75° = (√6+√2)/4

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Utsav Kumar 5 years, 1 month ago

sin ( A+ B) = sin75° Let A = 45° and B = 30° Then sin75° = sin45° cos30° + cos45° sin30° = 1/√2 * √3/2 + 1/√2 * 1/2 = √3 / 2√2 + 1/2√2 = √3 + 1/2√2 You can rationalise the denominator.

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