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Find the nature of the equation …

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Find the nature of the equation 2X^2-5X-7=0.
  • 3 answers

Parth Gupta 5 years, 1 month ago

2x^2-5x-7x=0 2x^2-5x-7 (2x^2-7x)+(2x-7) x(2x-7)+1(2x-7) (x+1)(2x-7)

Gaurav Seth 5 years, 1 month ago

Answer:the roots are not real

Step-by-step explanation:

comparing the equation in ax^2+bx+c=0

a=2

b=-5

c=7

Delta =b^2-4ac

         =25-4 x 2 x 7

         =25-56

         =   -31

It describes that the roots are imaginary or do not exist .

Gaurav Seth 5 years, 1 month ago

Answer:the roots are real and equal

Step-by-step explanation:

comparing the equation in ax^2+bx+c=0

a=2

b=-5

c=7

Delta =b^2-4ac

         =25-4 x 2 x 7

         =25-56

         =   -31

It describes that the roots are imaginary or do not exist .

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