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Find area of triangle whose two …

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Find area of triangle whose two sides are 18 cm and 10 cm .periemeter is 42 cm

    • Posted by P R I N C E 4 years ago

    CBSE > Class 09 > Mathematics
    • 3 answers

    12345 . 4 years ago

    Answer is 21 underroot 11 cm sq.

    1Thank You

    Palak Pandey 4 years ago

    I solve it with the herons formula and the answer is 11√21 cm^2

    0Thank You

    Gaurav Seth 4 years ago

    Given,
    Side a=18cm
    Side b=10cm
    Perimeter=42cm=a+b+c
    :. Putting value
    42=18+10+c
    42=28+c
    42-28=c
    14=c
    Now,
    S=(a+b+c)/2
    :. Putting value
    S=42/2
    S=21
    Now according to Heron's formula-
    Area of a triangle
    =√{s(s-a)(s-b)(s-c)}
    :. Putting value
    =√{21(21-18)(21-10)(21-14)}
    =√{21(3)(11)(7)}
    =√4851
    =21√11cm²

    1Thank You

    ANSWER
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