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In a triangle ABC, write cos …

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In a triangle ABC, write cos (B+C/2) in terms of Angel a

    • Posted by Deepak Karthick 5 years, 1 month ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Utsav Kumar 5 years, 1 month ago

    We know that, A+ B+ C = 180° B+C = 180° - A Dividing both sides by 2 B+C /2 = 90° - A/2 Taking cos on both sides, cos(B+C/2) = cos(90° - A/2) This gives, cos(B+C/2)= sin(A/2)

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