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In fig. PQ and PR are tangents to circle with centre O such that angleQPR =50

Posted by Riddhi Bishnoi 5 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 5 years, 1 month ago

In quad. PQOR,
∠R+ ∠O+ ∠Q+ ∠P = 360
∠P + ∠O = 90
∠O = 130
Now,
In ∆ROQ,
∠RQO + ∠QOR + ∠ORQ = 180°
Now as the sides OQ = RO because of radius of same circle... Hence.... OQR = 25°

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