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Aseem Mahajan 4 years, 2 months ago
$$\left|\hat{\imath} \;\;\;\;\;\;\; \hat{\jmath}\;\;\;\;\;\;\; \hat{k} \\ 1 \; \;\;\;\;\;\; 1\;\;\;\;\;\;\; -1 \\ 2 \;\;\;\;\;\;\; -1 \; \;\;\;\;\;\; 4 \right|$$
Solving for matrix , magnitude of cross product:
$$\hat{imath}(1 × 4 - (-1) × (-1)) - \hat{jmath}(1×4 - (-1) × 2) + \hat{k}(1 × -1 - (1 × 2)) \\ = 3\hat{\imath} - 6\hat{\jmath} - 3\hat{k}$$
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