If p times pth is same …

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Gaurav Seth 5 years, 6 months ago
p[a+(p−1)a]=q[a+(q−1)d]
ora(p−q)+(p2−q2)d+(q−p)d=0
ora(p−a)+(p+a)(p−q)−(p−q)d=0
ora+(p+q−1)d=0
This is the (p+q) th term.
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