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The sum of two numbers is 16 and their difference is 18

Posted by Raj Dewangan 5 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Prachi Jain 5 years, 1 month ago

510 = 92 x 5 + 50 92 = 50 x 1 + 42 50 = 42 x 1 + 8 42 = 8 x 5 + 2 8 = 2 x 4 + 0 ∴ HCF of 510 and 92 = 2 Product of two numbers = Product of their LCM and HCF 510 x 92 = 2 x LCM LCM = (510 x 92) / 2 = 23460 ∴ LCM of 510 and 92 = 23460.

1Thank You

Honey Jain 5 years, 1 month ago

X+Y =16------1eq. X-Y=18-----2nd. BY eliminate method X-Y=18 X+Y=16 THEN,-Y AND +Y Is cut After that 2X=16+18 THEREFORE , 2X=34 THEN,X= 17 Y= -1

1Thank You

Yogita Ingle 5 years, 1 month ago

Suppose one number is X,

And another be Y.

By first condition,

X+Y=16………….(1)

By second condition,

X-Y =18………….(2)

Adding both the equation,

X+Y=16

+X -Y=18

…………….

2x =34 (y,-y get cancelled)

X=17.

Substitute x=17 in (1),

17+y=16

Y=16–17

Y= -1

(x=17,y=-1).

0Thank You

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CBSE > Class 10 > Mathematics