In taingle ABC,DE parallel too AC …

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Posted by Prachi Jain 5 years, 1 month ago
- 4 answers
Yogita Ingle 5 years, 1 month ago
In △BPA, we have
DC∣∣AP [Given]
Therefore, by basic proportionality theorem, we have
BC/ CP = BD/DA ........ (I)
In △BCA, we have
DE∣∣AC
Therefore, by basic proportionality theorem, we have
BE/EC = BD/DA........ (iI)
From (i) and (ii), we get
BC/CP = BE/ EC or BE/EC = BC/CP [Hence proved]

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Prachi Jain 5 years, 1 month ago
2Thank You