Solve by substitution method : 2x …

Step 1: 2x+3y=9 ..............(eqn 1) 4x-6y=18 ............(eqn 2) divide equation 2 by 2 on both sides, we get: 2x - 3y = 9 2x = 9 + 3y x = (9+ 3y)/2 ..........(eqn 3) step 2: now put the value of x (from equation 3) in equation 1, we get: 2((9+ 3y)/2) + 3y = 9 (9 + 3y) +3y = 9 9 + 6y =9 6y = 9-9 6y = 0 y = 0 .........................(eqn 4) step 3: Now put the value of y = 0 (from equation 4) in equation 3, we get x = (9+ 3(0))/2 x = 9/2 x = 4.5 .......................(eqn 5) so the answer is x = 4.5 and y = 0. step 4: Verification: to verify the answer we can put these values of x and y in any one of the equation 1 or equation 2. put x = 4.5 and y = 0 in equation 1, we get 2x+3y=9 2(4.5) + 3(0) = 9 9 + 0 = 9 9 = 9 L.H.S. = R.H.S.

Step 1:

           2x+3y=9 ..............(eqn 1)

           4x-6y=18  ............(eqn 2)

divide equation 2 by 2 on both sides, we get:

           2x - 3y = 9

           2x = 9 + 3y

             x = (9+ 3y)/2   ..........(eqn 3)

 

step 2:

now put the value of x (from equation 3) in equation 1, we get:

            2((9+ 3y)/2) + 3y = 9

             (9 + 3y) +3y = 9

              9 + 6y =9

              6y = 9-9

              6y = 0

                y = 0   .........................(eqn 4)

 

step 3:

Now put the value of y = 0 (from equation 4) in equation 3, we get

           x = (9+ 3(0))/2

           x = 9/2

           x = 4.5  .......................(eqn 5)

so the answer is  x = 4.5 and y = 0.

 

step 4:

Verification:

to verify the answer we can put these values of x and y in any one of the equation 1 or equation 2.

put  x = 4.5 and y = 0  in equation 1, we get

             2x+3y=9

             2(4.5) + 3(0) = 9

              9 + 0 = 9

                9 = 9

            L.H.S. = R.H.S.

It means our answer is right.