Show that each of the progressions …

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Gaurav Seth 5 years ago
The given progression 9, 15, 21, 27,…………
Clearly, 15 – 9 = 21 – 15 = 27 – 21 = 6 (Constant)
Thus, each term differs from its preceding term by 6. So, the given progression is an AP.
First term = 9
Common difference =6
Next term of the AP = 27 + 6 = 33
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