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When an object is placed at a distance of 50 cm from converging mirror, the magnification produced is -½where the object should be placed to get magnification of-⅕

Posted by Krishna Yadav 5 years, 3 months ago

CBSE > Class 10 > Science

1 answers

Priya ✧*｡٩(๑˙╰╯˙๑)و✧*｡ 5 years, 3 months ago

maddy817 28.12.2018 Physics Secondary School +5 pts Answered when an object is placed at a distance of 50 cm from a concave spherical mirror the magnification produced is minus one by two where should the object be placed to get a magnification of minus 1 by 5? 1 SEE ANSWER ADD ANSWER Log in to add comment maddy817 is waiting for your help. Add your answer and earn points. Answer 4.4/5 180 knjroopa Ace 3K answers 2.6M people helped Given When an object is placed at a distance of 50 cm from a concave spherical mirror the magnification produced is minus one by two where should the object be placed to get a magnification of minus 1 by 5? So we have m = - v / u = - 1 / 2 - v = m x u Given u = 50 cm, m = - 1/2 - v = - 1/2 x 50 v = 50 / 2 or v = 25 cm 1 / f = 1 / u + 1 / v 1 / f = 1 / 50 + 1 / 25 f = 50 / 3 = 16.6 cm Now coming to magnification we have m = - v / u = - 1 / 5 given v / u = 1 / 5 5 v = u v = u / 5 or 1 / v = 5 / u 1 / f = 1 /u + 1 / v 3 / 50 = 1 / u + 5 / u 3 / 50 = 6 / u 3 u = 300 u = 300 / 3 u = 100 cm

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Posted by Pandey Ji 6 months ago

CBSE > Class 10 > Science