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Raoult' s law as special case …

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Raoult' s law as special case of Henry' s law

Posted by Romy Moon 5 years, 3 months ago

CBSE > Class 12 > Chemistry

3 answers

Shweta? Dhama? 5 years, 3 months ago

According Raoults law...the partial pressure of each component is directly proportional to mole fraction of solutions... Raoults law is given by...p=p*x where p is partial pressure or X Is mole fraction and p*is vapour pressure of pure component ... Henry's law is given by...p=kH x Where p is partial pressure and X Is mole fraction kH is proportionality constant ... Hence Raoults law is special case of Henry's law kH=p*...and both R.L and H.L obeyed in opposite composition ranges....hope so it helps u...?

Iqbal Singh 5 years, 3 months ago

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