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At 400°c the vapour pressure of …

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At 400°c the vapour pressure of water is 53.3 mm hg. Calculate the vapour pressure at same temperature over 10% aqueous solution of urea [co(nh2)2]

Posted by Ibarikmen Rynjah 5 years, 3 months ago

CBSE > Class 12 > Chemistry

2 answers

Aditya Shindhe 5 years, 3 months ago

53.48 mm Hg Solution : Mass of urea in 100 g of soution = 10 = 90 g Mass of water in the soltion=100−10=90gMass of water in the soltion=100-10=90g No. of moles of urea=(10g)(60g mol−1)=5.0molNo. of moles of urea=(10g)(60g mol-1)=5.0mol No. of moles of water(90g)(18g mol−1)=5.0molNo. of moles of water(90g)(18g mol-1)=5.0mol Mole fraction of water=(5.0mol)(5.0mol)+(0.17mol)=5.05.17=0.967Mole fraction of water=(5.0mol)(5.0mol)+(0.17mol)=5.05.17=0.967 Vapoure pressure of water over aquious solution =P∘water×Cwater=(55.3mm)×0.967Vapoure pressure of water over aquious solution =Pwater∘×Cwater=(55.3mm)×0.967 =53.48 mm Hg.

Rohiit Guptaa 5 years, 3 months ago

53.48 mm Hg Solution : Mass of urea in 100 g of soution = 10 = 90 g Mass of water in the soltion=100−10=90gMass of water in the soltion=100-10=90g No. of moles of urea=(10g)(60g mol−1)=5.0molNo. of moles of urea=(10g)(60g mol-1)=5.0mol No. of moles of water(90g)(18g mol−1)=5.0molNo. of moles of water(90g)(18g mol-1)=5.0mol Mole fraction of water=(5.0mol)(5.0mol)+(0.17mol)=5.05.17=0.967Mole fraction of water=(5.0mol)(5.0mol)+(0.17mol)=5.05.17=0.967 Vapoure pressure of water over aquious solution =P∘water×Cwater=(55.3mm)×0.967Vapoure pressure of water over aquious solution =Pwater∘×Cwater=(55.3mm)×0.967 =53.48 mm Hg.

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