Five year ago Nuri was thrice …

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Posted by Sejal Thakur 5 years, 2 months ago
- 2 answers
Yogita Ingle 5 years, 2 months ago
Let the present age of Nuri =x year
And present age of Sonu =y year
Five years ago
Age of Nuri =x–5years
Age of Sony =y–5years
Nuri was thrice as old as Sonu
X−5=3(y–5)
X–5=35–15
X–3y=−15+5
X–3y=−10 ………..(1)
Ten years later,
Age of Nuri =x+10
Age of Sonu =y+10
Nuri will be twice as old as Sonu.
X+10=2(y+10)
X+10=2y+20
X–2y=10 ………..(2)
X–3y=−10 ………..(1)
Subtracting equation (1) from equation (2) we get
Y=20
Plug this value in equation first we get
X−3∗20=−10
X=60–10
X=50
Hence age of Nuri =50 years and age of Sonu =20 years
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Sejal Thakur 5 years, 2 months ago
0Thank You