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Prove that 3+√5 is irratonal

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Prove that 3+√5 is irratonal
  • 3 answers

Malaika Sharma 5 years, 2 months ago

Let us assume 3+root 5 to be rational.It means that it can be written in the form of p/q where p and q are coprime and q is not equal to zero L.H.S *p/q=3+root5 *p/q-3=root5 L.H.S i.e.p/q-3 is rational but R.H.S i.e. root 5 is irrational So our assumption is wrong Therefore 3+root5 is irrational.

Anshul Agarwal 5 years, 2 months ago

Hence proved

Riya Sharma 5 years, 2 months ago

Let us assume that 3+5​ is a rational number. Now, 3+5​=ba​ [Here a and b are co-prime numbers] 5​=[(ba​)−3] 5​=[(ba−3b​)] Here, [(ba−3b​)] is a rational number. But we know that 5​ is an irrational number. So, [(ba−3b​)] is also a irrational number. So, our assumption is wrong. 3+5​ is an irrational number. Hence, proved.
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