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Find sum of first 30 integers …

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Find sum of first 30 integers divisible by 8

Posted by Kashish Dua 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Riya Philip 5 years, 2 months ago

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Yogita Ingle 5 years, 2 months ago

The number series 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, . . . . , 240.

The first term a = 8

The common difference d = 8

Total number of terms n = 30

step 2 apply the input parameter values in the AP formula

Sum = n/2 x (a + Tn)

= 30/2 x (8 + 240)

= (30 x 248)/ 2

= 7440/2

8 + 16 + 24 + 32 + 40 + 48 + 56 + 64 + 72 + 80 + 88 + 96 + . . . . + 240 = 3720

Therefore, 3720 is the sum of first 30 positive integers which are divisible by 8

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CBSE > Class 10 > Mathematics