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Sides of triangle are in the ratio 11 : 19 : 24 and its perimeter is 540 find the area of the triangle

    • Posted by Vasu Singhal 18 4 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Ayush Thakur 4 years, 1 month ago

    Let the sides be 11x, 19x, 24x Perimeter = a+b+c 540 = 11x + 19x + 24x 540 = 54x 540/54 = x 10 = x 11x = 11×10= 110 19x = 19×10= 190 24x = 24×10= 240 These are the sides of triangle. Area of triangle = √s(s-a)(s-b)(s-c) (s means semi-perimeter ) s = perimeter/2 = 540/2 = 270 Area of triangle √s(s-a)(s-b)(s-c) =√270(270-110)(270-190)(270-240) = √ 270(160)(80)(30) = 10182.34

    1Thank You

    Yogita Ingle 4 years, 1 month ago

    Let the ratio be 11x 19x and 24x

    11x +19x+24x =540

    54x =540 .: x = 540/54

    Hence x=10

    11x =11×10=110 19x= 19×10 =190

    24x=24 × 10 =240

    1Thank You

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