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Find the zeroes of the following …

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Find the zeroes of the following quadratic polynomial 4u^2+8u
  • 2 answers

Samraat Sahil Verma 5 years, 2 months ago

4u^2+8u=4u(u+2) Either 4u=0 =u=0/4=0 Or u+2=0 =u=-2 Zeros are 0,-2 Sum of zeros=o+(-2)=-2=-8/4=-(Coefficient of u)/(Coefficient of u^2) Product of zeros=0×(-2)=0=0/4=constant term/Coefficient of u^2

Sadhna Sadhna 5 years, 2 months ago

4u
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