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Prove that in a right triangle, …

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Prove that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides
  • 1 answers

Rohit Kumar 5 years, 2 months ago

Given:- A right triangle ABC right angled at B. To prove:- AC2=AB2+BC2 Construction:- Draw BD⊥AC Proof:- In △ABC and △ABD ∠ABC=∠ADB(Each 90°) ∠A=∠A(Common) ∴△ABC∼△ABD(By AA) ACAB​=ABAD​(∵Sides of similar triangles are proportional) ⇒AB2=AD⋅AC.....(1) Similarly, in △ABC and △BCD ∠ABC=∠BDC(Each 90°) ∠C=∠C(Common) ∴△ABC∼△BCD(By AA) ∴BCDC​=ACBC​ ⇒BC2=DC⋅AC.....(2) Adding equation (1)&(2), we have AB2+BC2=AD⋅AC+DC.AC ⇒AB2+BC2=AC(AD+DC) ⇒AB2+BC2=AC2 Hence proved. 
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