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factorise (a2-b2)3+(b2-c2)3+(c2-a2)3

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factorise (a2-b2)3+(b2-c2)3+(c2-a2)3

Posted by Divyanshi Poddar 4 years, 10 months ago

CBSE > Class 09 > Mathematics

4 answers

Sarita Panda 4 years, 10 months ago

By using the identity a³+b³+c³-3abc a=a²-b² b=b²-c² c=c²-a² if a+b+c=0 then a³+b³+c³=3abc On Adding we will get 0 => Ans would be= 3×(a²-b²)(b²-c²)(c²-a²) =(3)(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)

Vaibhav Kumar 4 years, 10 months ago

Any more questions

Vaibhav Kumar 4 years, 10 months ago

I hope the answer is useful

Vaibhav Kumar 4 years, 10 months ago

* = multiple ; =(a⁶ - b⁶ - 3*a⁴b²+ 3*a²b⁴) + ( b⁶- c⁶ - 3*b⁴c²+ 3*b²c⁴) + ( c⁶- a⁶ - 3*c⁴a² + 3*c²a⁴) = Now , Cut the no. -Minus +plus Minus plus cut kardo bracket hata ke = a⁶ - b⁶ - 3a⁴b²+ 3a²b⁴+ b⁶- c⁶ - 3b⁴c²+ 3b²c⁴ + c⁶- a⁶ - 3c⁴a² + 3c²a⁴ = Now , a⁶ ko -a⁶ se cut karo same with b⁶ ko -b⁶ se cut karo and c⁶ ko -c⁶ se cut karo =we get, = -3a⁴b² + 3a²b⁴-3b⁴c²+ 3b²c⁴ - 3c⁴a² + 3c²a⁴

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