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-5 is one the zeroes of 2x^2 +px -15, zeroes of p(x^2+x)+k are equal to each other. Find value of k

Posted by Manav Sharma 5 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Manav Sharma 5 years, 2 months ago

P(x)= 2x^2+px-15 Zero is given -5 P(-5)=0 Than 2(-5)^2+p(-5)-15=0 50-5p-15=0 35=5p 7=p Put value of p in p(x^2+x)+k 7x^2+7x+k By using b^2-4ac=0 49-28k=0 K=-49/-28=7/4 Thanks

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CBSE > Class 10 > Mathematics