The base PQ of two equilateral …

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Yogita Ingle 5 years, 2 months ago
Since the mid point of PQ is the origin and PQ = 2a
Hence the coordinates of P and Q are (0,a) and (0,-a) respectively.
Since triangles PQR and PQR' are equilateral
X'OX is the perpendicular bisector of base PQ.
Thus R and R' lies on X-axis,
In
ROP, OR2 + OP2 = PR2
Similarly,
=
Thus,the coordinates of the vertices R and
are
respectively.
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