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The base PQ of two equilateral …

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The base PQ of two equilateral triangles PQR and PQR’ with side 2a lies along y- axis such.that the mid-point of PQ is at the origin. Find the coordinates of the vertices R and R’ of the triangles.
  • 1 answers

Yogita Ingle 5 years, 2 months ago

Since the mid point of PQ is the origin and PQ = 2a

OP = OQ = a

Hence the coordinates of P and Q are (0,a) and (0,-a) respectively.

Since triangles PQR and PQR' are equilateral

Their third vertices R and R' lie on the perpendicular bisector of base PQ.

X'OX is the perpendicular bisector of base PQ.

Thus R and R' lies on X-axis,

 their Y coordinates are zero.

In ROP, OR2 + OP2 = PR2

 OR2 + a2 = (2a)2

 OR2 = 3a2

OR = 

Similarly,  =

Thus,the coordinates of the vertices R and  are  respectively.

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