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A circle touches all the four sides of a quadrilateral abcd in which ab=6 cm, bc=7 cm, and CD=4 cm, find ad

Posted by Deepak Mandal 5 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Harish Sharma 5 years, 2 months ago

0Thank You

Gaurav Seth 5 years, 2 months ago

Since, length of two tangents drawn from an external point of circle are equal.
So,    AP = AS
BP = BQ DR = DS
and    RC = CQ
Adding all, we get
(AP + BP) + (DR + RC) = AS + BQ + DS + CQ
⇒ (AP + BP) + (DR + RC)
= (AS + DS) + (BQ + CQ)
⇒    AB + DC = AD + BC
⇒    6 + 4 = AD + 7
⇒    10 = AD + 7
AD = 10 – 7 = 3 cm
Hence, AD = 3 cm.

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