No products in the cart.

method of preparing fixture in knock_out …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

method of preparing fixture in knock_out tournament
  • 1 answers

Gaurav Seth 3 years, 10 months ago

Tournament is a large contest of many rounds among various teams. It is a competition held among various teams in a particular activity according to a fixed schedule where a winner is decided.
Number of teams participating are 27.
Number of matches = n – 1 = 27 – 1 = 26 matches.
Teams in upper half = n+1/2=27+1/2= 28/2
Teams in lower half = n−1/2=27−1/2= 26/2 = 13 teams
Number of teams participating are odd so number of byes will be = 32 – 27 = 5 byes.
In Knockout system the team which loses the match is eliminated and the winners continue to play. When we have less time usually we conduct single elimination tournament.
Date/time and court number, is specified for each match so that teams/players report for their matches well in advance.

http://mycbseguide.com/examin8/

Related Questions

Tadasan
  • 0 answers
Equipment for kabaddi
  • 0 answers
What is proficiency in sports
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App