Find the zeros of the polynomial …
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Gaurav Seth 5 years, 2 months ago
=6x²-7x-3
=6x²+2x-9x-3
=2x(3x+1)-3(3x+1)
=(2x-3)(3x+1)
⇒2x-3=0 or ⇒3x+1=0
⇒x=3/2 or ⇒ x= - 1/3
α=3/2 ,β= - 1/3
⇒α+β= -b/a
⇒3/2+(-1/3)= - (-3)/6
⇒3/2-1/3=1/2
⇒7/6 =1/2
⇒αβ=c/a
⇒ 3/2(-1/3)= -7/6
⇒-1/2= -7/6
⇒1/2=7/6
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