In triangle ABC, let angle A=120° …
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Posted by . . 4 years, 2 months ago
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Gaurav Seth 4 years, 2 months ago
This ΔABC is an isosceles triangle. In this kind of triangle, two of the sides are equal.
So if AB=AC,
Then vertex= angle A and
Base angles= angle B and angle C which are equal.
Let the base angles angle B and angle C be x.
Since the sum of the angles of a triangle=180°,
Therefore,
angle A + angle B + angle C = 180°
= 120° + x+x= 180°
= 120° + 2x= 180°
= 2x = 180°-120°
= 2x = 60°
= x = 60°/2 =30°
Therefore,
Angle A= 120°
Angle B= 30°
Angle C= 30°.
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