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for what value of k,x=1,y=0,is a solution of[k+2/k-1]x -[3k-2/k+2]y-3=0. plz give me answer.

Posted by Rohan Patil 5 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 5 years, 3 months ago

Put x=1,y=0
[k+2/k-1]x -[3k-2/k+2]y-3=0

(k²+ 2 - k)/k] 1 -[3k-2/k+2]0-3=0
(k²+ 2 - k)/k] = 3

k²+ 2 - k = 3k

k²+ 2 - k -3k = 0

k² -4k+ 2= 0

1Thank You

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CBSE > Class 09 > Mathematics