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tanA/(1-cotA) +cotA/(1-tanA)= (1+tanA+cotA) plz. gave me …

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tanA/(1-cotA) +cotA/(1-tanA)= (1+tanA+cotA) plz. gave me a solution plz

    • Posted by Tushar Teotia 5 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Yash Kumar 5 years, 3 months ago

    tanA/(1–cotA) + cotA(1–tanA) tanA/(1–1/tanA) + 1/tanA(1–tanA) tanA/tanA–1/tanA + 1/tanA(1–tanA) tan²A/tanA–1 + 1/tanA(1–tanA) tan²A/tanA–1 —1/tanA(tanA–1) tan³A–1/tanA(tanA–1) (tanA–1)(tan²A+1+tanA)/tanA(tanA–1) tan²A/tanA + 1/tanA +tanA/tanA tanA + cotA + 1 1 + tanA + cotA

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